Question

The floor of a building consists of 3000 tiles which are Rhombus shaped and each of its diagonal are 45 cm and 30 cm in length find the total cost of polishing the floor if the cost per metre square is 4.​

Answer 1

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An First finding the area of a rhombus shaped tile.

Area of a rhombus is given by,

Area of a rhombus= d¹×d²/2

where d₁ is the first diagonal,

d₂ is the second diagonal

Substitute the data,

Area of the tile = (45 × 30)/2

⇒ 1350/2

⇒ 675 cm²

Hence the area of each tile is 675 cm²

Therefore,

Area of 3000 tiles = 3000 × Area of 1 tile

⇒ 3000 × 675

⇒ 2025000 cm² = 202.5 m²

Now the total cost of polishing is given by,

Cost of polishing = Area of the tiles × Rate per m²

⇒ 202.5 × 4

⇒ 810 rupees Ans.

Answer 2

Step-by-step explanation:

first find the area of rhombus= 1/2× d¹ × d²