The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm 30 cm in length . Find the cost of polishing the floor at the rate of rs 4per m*2?
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area of each tile = 1/2(45cm×30cm)
=675cm^2
area of the floor = 3000×675/100
20,250m^2
cost of polishing the floor = 20,250×4=81000
=675cm^2
area of the floor = 3000×675/100
20,250m^2
cost of polishing the floor = 20,250×4=81000
Answered by
4
Area of rhombus =1/2
(Product of its diagonals)
Area of each tile
{1\2×45×30}cm^2
= 675 cm^2
Area of 3000 tiles = (675 × 3000) cm^2 = 2025000 cm^2 = 202.5 m^2
The cost of polishing is Rs 4 per m^2.
Cost of polishing 202.5 m^2 area = Rs (4 × 202.5) = Rs 810
Thus, the cost of polishing the floor is Rs 810.
(Product of its diagonals)
Area of each tile
{1\2×45×30}cm^2
= 675 cm^2
Area of 3000 tiles = (675 × 3000) cm^2 = 2025000 cm^2 = 202.5 m^2
The cost of polishing is Rs 4 per m^2.
Cost of polishing 202.5 m^2 area = Rs (4 × 202.5) = Rs 810
Thus, the cost of polishing the floor is Rs 810.
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