Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of it's diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor, if the cost per m2 is rupees 4

Answer 1

Answer:

I can't

Step-by-step explanation:

undetatand your answer

Answer 2

Answer:

Ans To find,

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tile

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right)

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 2

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 2

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30 =202.5\ m^2=202.5 m

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30 =202.5\ m^2=202.5 m 2

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30 =202.5\ m^2=202.5 m 2

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30 =202.5\ m^2=202.5 m 2 Cost of polishing=4times202.54×202.5

Ans To find,Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m 2 Area of floor=3000\times area\ of\ tile3000×area of tileArea of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right) 21 (product of its diagonals)=\frac{1}{2}\times45\times30 21 ×45×30 =202.5\ m^2=202.5 m 2 Cost of polishing=4times202.54×202.5=rs 810

(copied from Googl*)