The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the cost of polishing the floor at the rate of Rs.4 per m^2.
Answers
Answer:
To find,
Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m2
Area of floor=3000\times area\ of\ tile3000×area of tile
Area of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right)21(product of its diagonals)
=\frac{1}{2}\times45\times3021×45×30
=675\ cm^2675 cm2
Area of floor=3000\times675\ cm^23000×675 cm2
=2025000\ cm^2=2025000 cm2
=202.5\ m^2=202.5 m2
Cost of polishing=4\times202.54×202.5
=rs 810
Step-by-step explanation:
Hope's it helps you
Answer:
Answer is ₹810.
Step-by-step explanation:
SOLUTION
Given,
d1 = 45cm
d2 = 30cm
Area of one tile = Area of rhombus = 1/2 d1 × d2
=> (1/2 × 45 × 30) cm²
=> 675 cm².
Area of 3000 tiles = 3000 × area of one tile
=> (3000 × 675) cm²
=> 2025000 cm²
=> 2025000/100 × 100 m²
=> 202.5 m²