Question

The floor of a building consists of 3000 tiles which are rhombus shaped. The diagonals of
each of the tiles are 45 cm and 30 cm. Find the total cost of polishing the floor, if cost per
mºis 2.50.​

Answer 1

Answer:

⇒ Given,

       d1 = 45 cm

       d2 = 30 cm

       cost of polishing the floor = ₹ 2.5

⇒  Area of one rhombus-shaped tiles = d1 × d2

                                                          = 45 cm × 30 cm

                                                          =  1350 cm²

⇒ Area of 3000 rhombus-shaped tiles = 3000 tiles × 1350 cm²

                                                                 = 4050000 cm²

⇒ 1 m² = 100 cm × 100 cm²

           =  10000 cm²

⇒ converting 4050000 cm² to m²

⇒  4050000 cm² / 10000 cm²

⇒  405 m²

⇒ Cost of polishing the floor

⇒  405 m² × ₹ 2.5

⇒ ₹ 1012.5

∴  The cost of polishing the floor is ₹ 1012.5.