Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor, if the cost per m² is ₹ 4.​

Answer 1

Answer:

Rs. 810

Step-by-step explanation:

Given:

Total Number of tiles used = 3000

Since tiles is the shape of rhombus and Diagonals are 45 cm and 30 cm

Thus,

$d_{1} = 30 \: cm$

$d_{2} = 45 \: cm$

Area of one tile = Area of rhombus

$\frac{1}{2} \times d_{1} \times d_{2}$

$\frac{1}{2} \times 30 \times 45$

$15 \times 45$

$675 \: c {m}^{2}$

Area of 3000 tiles = 3000 × Area of 1 tile

= 3000 × 675

= 20250000 cm²

Now we have to find cost

Since cost is given per m²

We need to convert area into m²

Area = 20250000 cm²

$= 20250000 \times ( \frac{1}{100} {)}^{2} \: {m}^{2}$

$= \frac{20250000}{10000} \: {m}^{2}$

$= 202.5 \: {m}^{2}$

Now

Cost of polishing 1 m² = 4

Cost of polishing 202.5 m² = 4 × 202.5

$= 4 \times \frac{2025}{10}$

$= 4 \times \frac{405}{2}$

$= 810$

Total cost of polishing the floor = Rs 810

Answer 2

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