The floor of a building consists of 3000 tiles which are rhombus shaped and each of ita diagonals are 45 cm and 30cm in length. find the total cost of polishing the floor, if the cost per m square is rupees 4
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Answer:
Step-by-step explanation:
Area pf 1 rhombus in meter os equal to1/2×0.45m×0.3m
Which os equal to 0.135/2m^2
Now ar of 3000 rhombus tiles is equals to
3000×0.135/2
405/2
Now cost for polishing a tile is equals to ₹4
Therefore cost for polishing 3000 tiles is equals to total area of 3000 tiles ×₹4
Which is equlas to 405/2 ×4
=₹810 answer
I HOPE THIS ANSWER IS CORRECT
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