Question

the floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. find total cost of polishing the floor if the cost per m square is rs 4

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Answer 1

Given:

d1= 45cm , d2= 30cm

Number of tiles= 3000

Rate per m²= ₹4

Area of Rhombus= 1/2×d1×d2



= (1/2) × 45 × 30=675

Area of 1 tile= 675 cm² = 675/10000 m²

Area of 3000 tiles= 3000 × (675/10000)

[1cm²= 1/10000m²]

cost of Polishing the floor

= Total Area × rate



= (3000 × 675 ×4)/10000

= 3× 675×4/10

= 3× 67.5×4

= 12× 67.5

= ₹ 810

Hence the total cost of polishing the floor
= ₹ 810

Answer 2

Tiles are in the shape of rhombus

d1=45cm=0.45m

d2=30=0.30m

(where d stands for diagonals)

As we know area of rhombus=d1*d2

=0.45*0.30

= 0.135m^2

Total area to be polished= 300*0.135

=40.5m^2

Therefore, rate=40.5*4

=Rs.162

Hope this helps....