Question

The floor of a building consists of 3000 tiles which are of rhombus shape and each of its diagonal are 45 cm and length is 30 find the cost of polishing the floor if the cost per meter is ₹4.

Answer 1

The answer is given below :

Area of each rhombus shape tile

= (product of the diagonals)/2

= (45 × 30)/2 cm²

= 1350 cm²

So, area of 3000 tiles

= 3000 × 1350 cm²

= 4050000 cm²

= 405 m² [since 1 m² = 10000 cm²]

So, the cost of polishing is

= Rs (4 × 405)

= Rs 1620

Thank you for your question.

Answer 2

Answer:

Cost of polishing = Rs. 810

Step-by-step explanation:

$\sf\red{given :-}$

Diagonals of the rhombus = 45 cm and 30 cm

Total number of tiles = 300

Cost of polishing = Rs. 4 per m²

$\sf\blue{to\:find :-}$

The total cost of polishing all the tiles

$\sf\green{solution :-}$

First finding the area of a rhombus shaped tile.

Area of a rhombus is given by,

$\boxed{\tt Area\:of\:a\:rhombus=\dfrac{d_1\times d_2}{2}}$

where d₁ is the first diagonal,

d₂ is the second diagonal

Substitute the data,

Area of the tile = (45 × 30)/2

⇒ 1350/2

⇒ 675 cm²

Hence the area of each tile is 675 cm².

Therefore,

Area of 3000 tiles = 3000 × Area of 1 tile

⇒ 3000 × 675

⇒ 2025000 cm² = 202.5 m²

Now the total cost of polishing is given by,

Cost of polishing = Area of the tiles × Rate per m²

⇒ 202.5 × 4

⇒ 810 rupees

Hence the total cost of polishing the floor is 810 rupees.