Question

The floor of a building consists of 30000 tiles which are rhombus shaped and each of it's diagonal are 45 cm and 30 cm in length.find the total cost of polishing the floor, if the cost per m2 is ₹ 4
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Answer 1

Step-by-step explanation:

HEY MATE..........

$given \: \\ \\ total \: no. \: of \: tiles \: used \: = 3000 \\ \\ since \: tile \: is \: in \: the \: shape \: of \: rhombus \: and \: diagonals \: are \: 45cm \: and \: 30 \: cm \: \\ \\ thus \: \\ \\ d1 = 30cm \: \\ d2 = 45cm \: \\ \\ area \: of \: one \: tile \: = area \: of \: rhombus \: \\ \\ = \frac{1}{2} \times d1 + \times d2 \\ \\ = \frac{1}{2} \times 30 \times 45 \\ \\ = 15 \times 45 = 675 {cm}^{2} \\ \\ area \: of \: 3000 \: tiles \: = 3000 \times area of \: 1 \: tile \: \\ \\ = 3000 \times 675 = 2025000 {cm}^{2} \\ \\ now \: we \: need \: to \: find \: cost \: \\ since \: cos t \: is \: give \: in \: {m}^{2} \\ \\ we \: need \: to \: convert \: the \: area \: into \: {m}^{2 } \\ \\ area \: = 2025000 {cm}^{2} \\ \\ = 2025000 \times (\frac{ {1}^{2} }{100} ) {m}^{2} \\ \\ = \frac{2025000}{10000} {m}^{2} = 202.5 {m}^{2} \\ \\ now \: \\ cost \: of \: polishing \: 1 {m}^{2} = 4 \\ \\ cost \: of \: publishing \: 202.5 {m}^{2} = 4 \times \frac{2025}{10} = 4 \times \frac{405}{2} = 810 \\ \\ total \: cost \: of \: polishing \: the \: floor \: =rs. 810$

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