Question

The floor of a building consists of 3000tiles which are rhombus shaped and each of its diagonals are 45cm and 30cm in length. Find total cost of polishing the floor, if the cost per m² is Rs4.​

Answer 1

Solution➜

☞ Given:The floor of a building consists of 3000tiles which are rhombus shaped and each of its diagonals are 45cm and 30cm in length. Find total cost of polishing the floor, if the cost per m² is Rs4.

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☞Formula used:Area of rhombus and conversion of cm² to m².

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Let's solve:

Area of 1 rhombus=

$\frac{d1 \times d2}{2}$

$\frac{45cm \times 30cm}{2}$

$675 {cm}^{2}$

AREA OF 3000 rhombus=

675cm×3000=2025000cm²

To convert in m² we will divide by

10000.

$\frac{2025000}{10000}$

$202.5 {m}^{2}$

Cost of polishing per m²=₹4

Cost of polishing 202.5m²=

$202.5 {m}^{2} \times rs4 = rs810$

HENCEFORTH, THE COST OF POLISHING THE FLOOR IS ₹810.

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HOPE IT HELPS FROM MY SIDE

Answer 2

Answer:

₹810

Step-by-step explanation:

thx for giving me thnx

plz asked A question in subject Chinese plz