Question

The floor of a building consists of 400 tiles which are rhombus shaped and each of it diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor if the cost per m2 is ` ₹ 10

Answer 1

Diagonals of the Rhombus:-

D1 = 45

D2 = 30

Using Formula.:

Are of Rhombus = 1/2 × D1 × D2

Area of 1 Rhombus :-

= $\frac{1}{2}$ × 45 × 30

= 45 × 15

Area of 1 Rhombus= 675cm²

Area of Floor :

= 400 × 675

= 2,70,000 cm²

So, Cost of Polishing the floor:

= 2,70,000 × 10

= 27,00,000 rs