The floor of a building consists of 5000 tiles which are rhombus shaped and
each of its diagonals are 55 cm and 40 cm in length. Find the total cost of
polishing the floor, if the cost per m2 is ₹ 5
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Answer:
Rs.2750
Step-by-step explanation:
Diagonals of rhombus = 55 and 40 cm
Area of tile = 1/2 × 55 × 40 cm² = 1100 cm² = 0.11 m²
Area of floor = 5000×0.11 m² = 550 m²
Cost of polishing per m² = Rs.5
Total cost of polishing = Rs.5×550 = Rs.2750
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