The floor of a building consists of 5000 which are rhombus shaped and each of diagonals is 30cm and 20cm in length. Find the total cost of polishing the floor if the cost per m² is ₹ 3
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1 floor of a building consist = 5000 rooms
each of diagnols of rhombus shaped rooms = 30m
and length = 20 m
area of each room = l x b = 20 x 30 = 600 m²
area of one floor = 600 x 5000 = 30,00,000m²
cost of polishing the floor per m² = Rs. 3
total cost of polishing the floor = 30,00,000 x 3 = Rs. 90,00,000
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