Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each
of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile
costs rupees 20 per m²
​

Answer 1

Answer:

₹4050

Step-by-step explanation:

area of rhombus shaped tiles =1/2(product of diagnose)

45cm=45/100m,30cm=30/100m

=>area of tile = 1/2×45/100×30/100=1/2×9/20×3/10

=>area of tile = 27/400m²

A. T. Q,

total number of tiles =3000

=>total area=3000×27/400=30×27/4=810/4

=>total area =202.5m²

cost per m²=₹20

=>total cost = 20×2025/10=2×2025=₹4050

Hope it helps you..

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Answer 2

Answer:

4050

Step-by-step explanation:

• Length of diagonals of rhombus=45cm,30cm.

• Area of tile=1/2d1d2

• 1/2×45×30

• 675sqcm

• Area of 3000 tiles=675×3000

=2025000sqcm

=2025000/100×100

=2025/10

=202.5sqcm

=202.5×20

=4050

Hope it helps you•••

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