Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each
of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile
costs rupees 20 per m²​

Answer 1

Answer:

Rs.4050

Step-by-step explanation:

Diagonals of tile = 0.45 m and 0.30 m

Area of 1 tile = 1/2 × 0.45 × 0.3 m² = 0.0675 m²

Area of 3000 tiles = 0.0675 × 3000 m² = 202.5 m²

Cost per m² = Rs.20

Hence, total cost = Rs.(20×202.5) = Rs.4050