Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each
of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each sle
costs rupees 20 per m².​

Answer 1

Answer:

Rs 4050

Step-by-step explanation:

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Answer 2

Given Question :-

• The floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile costs rupees 20 per m².

ANSWER

GIVEN :-

• The floor of a building consists of around 3000 tiles which are rhombus shaped.

• Diagonals are 45 cm and 30 cm in length.

TO FIND :-

• The total cost of flooring if each tile costs rupees 20 per m².

FORMULA USED :-

$\boxed {\bull{ \green{ \bf \:Area_{(rhombus)} = \dfrac{1}{2} \times product \: of \: diagonals }}}$

CALCULATION :-

Given,

• Dimensions of rhombus tile,

• Length of first diagonal = 45 cm

• Length of second diagonal = 30 cm

So,

• Area of 1 tile is given by,

$\rm :\implies\:Area_{(tile)} = \dfrac{1}{2} \times 45 \times 30$

$\rm :\implies\:Area_{(tile)} \: = \: 675 \: {cm}^{2}$

$\rm :\implies\:Area_{(tile)} \: = \: 0.0675 \: {m}^{2} \: \{1 \: {m}^{2} = 10000 {cm}^{2} \}$

Now,

• Area of 3000 tiles is given by

$\rm :\implies\:Area_{(3000 \: tiles)} \: =0.0675 \times 3000$

$\rm :\implies\:Area_{(3000 \: tiles)} \: = \: 202.5 \: {m}^{2}$

So,

Cost of flooring tile at the cost of Rs 20 per m² is given by

$\rm :\implies\:Cost_{(flooring)} = 202.5 \times 20$

$\longmapsto \boxed{ \green{ \bf \:Cost_{(flooring)} = Rs \: 4050 }}$