Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each
of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile
costs rupees 20 per m2​

Answer 1

Step-by-step explanation:

ABCD be a tile, such that BD = 45cm & AC = 30cm

Area of each tile =

2

AC×BD

=

2

45×30

=675cm

2

Area of 3000 tiles = 300×675=2025000cm

2

=202.5m

2

Cost of flooring = Rs.(202.5×20)=Rs.4050

Answer 2

$Area \: of \: rhombus \: tile = \frac{1}{2} \times d_{1} \times d_{2}$

$Area \: of \: tile \: = \frac{1}{2} \times 45 \times 30$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 675 \: {cm}^{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6.75 \: {m}^{2}$

$Cost \: of \: 1 \: {m}^{2} = 20$

$cost \: of \: 1 \: {m}^{2} \: flooring= rs. \: 20 \:$

$Cost \: of \: flooring \: 6.75 \: {m}^{2} = 6.75 \times 3000$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20250$

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