Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each
of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile
costs rupees 20 per m2?​

Answer 1

We are given a rhombus shaped tile whose diagonals are 45 cm and 30 cm in length.

We need to find the total cost of flooring if one tile costs Rs.20 per m².

Let us find the area of the rhombus shaped tile. We know that:

⟼ Area of Rhombus = Product of Diagonals/2

⟼ Area of Rhombus = 45×30/2

⟼ Area of Rhombus = 1350/2

⟼ Area of Rhombus = 675 cm²

Thus, we have found area of one tile. Let us convert the centimetre square units to metre square units. We know that,

⟼ 1 cm² = 1/10000 m²

Therefore,

⟼ Area of Rhombus = 675 cm²

⟼ Area of Rhombus = 675/10000 m²

⟼ Area of Rhombus = 0.0675 m²

According to the Question,

⟼ Area of one tile = 0.0675 m²

⟼ Area of 3000 tiles = 3000×0.0675 m²

⟼ Area of 3000 tiles = 202.5 m²

Finally, let us find the total cost of flooring:

⟼ Cost of flooring = Area of 3000 tiles × Cost of each tile

⟼ Cost of flooring = 202.5 × 20

⟼ Cost of flooring = Rs.4050

Hence, the total cost of flooring is Rs.4050

Answer 2

Area of rhombus = 1/2 x (diagonal x diagonal) = 1/2x45x30 = 675cm. So area of 1 tile = 675cm. Area of 3000 tiles = 675x3000 = 202500. First we have to convert cm into m. So , 202500cm = 2025m. So, the total cost of flooring the whole building = 2025 x 20 = 40500 rupees. Therefore 40500 rupees is the answer.
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