Question

the floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonal are 45cm and 30cm in length. find the total cast o.t of flooring if each tile cost ruppes 20 per m^2.​

Answer 1

Answer:

To find,

Cost of polishing=area\ of\ floor\times\cos t\ per\ m^2area of floor×cost per m

2

Area of floor=3000\times area\ of\ tile3000×area of tile

Area of a tile=\frac{1}{2}\left(product\ of\ its\ diagonals\right)

2

1

(product of its diagonals)

=\frac{1}{2}\times45\times30

2

1

×45×30

=675\ cm^2675 cm

2

Area of floor=3000\times675\ cm^23000×675 cm

2

=2025000\ cm^2=2025000 cm

2

=202.5\ m^2=202.5 m

2

Cost of polishing=4\times202.54×202.5

=rs 810

Step-by-step explanation:

hope it helps