The floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonal are 45cm and 25cm in length. Find the total cost of flooring if each tile costs rupees 20 per m².
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Solution: Length of one diagonal, d1 = 45 cm and d2= 30 cm
Area of one tile = 1/2 d1 d2
= ½ x 45 x 30 = 675
Area of one tile is 675 cm^2
Area of 3000 tiles is
= 675 3000 = 2025000 cm^2
=2025000/ 10000
= 202.50 m^2
Cost of polishing the floor per sq. meter = 4
Cost of polishing the floor per 202.50 sq. meter = 4 x 202.50 = 810
Hence the total cost of polishing the floor is Rs. 810.
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