Question

The floor of a building consists of around 3000 times which are rhombus shaped and each of its diagonals are 45cm and 30cm in length find the total cost of flooring if each tile costs rupees 20 per m2

Answer 1

Hi friend,

Area of one tile-:

D1=45 cm
D2=30 cm
Area= 1/2*d1*d2
=1/2*45*30
=675 cm^2

Area of 3000 tiles-:

675*3000=202500cm^2
=202.5 m^2

Cost of flooring 1 m^2=₹20
Cost of flooring 202.5m^2=202.5*20
=₹4050 for flooring the floor.

Hope it helped you.........................

Answer 2

D1 = 45
D2 = 30
Area of rhombus = 1/2 *45*30
= 675 cm2
3000 tiles= 3000 * 675 = 2025000= 2025m2
1 m2 costs= rupees 20
Therefore 2025 m2 costs= 40500 rupees



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