The floor of a building contains of 300 tiles which are Rhombus shaped and each of the its diagonal are 30cm and 45 CM in length find the total cost of polishing the floor if thecost per metre square is rupees 4
Answers
Answer:
The cost for polishing will be Rs 81.
Step-by-step explanation:
There are 300 tiles each of rhombus shaped .
Now the diagonals of the rhombus are given .
The diagonals are 30 cm and 45 cm .
We have to find the cost of polishing the floor.
This means that we have to find the area of all the tiles and hence we have to find the area of each rhombi .
The area of the rhombus is given by the formula :
Area = 1/2 × product of diagonals.
The diagonals are 30 cm and 45 cm.
So area = 1/2 × 30 cm × 45 cm
= 15 cm × 45 cm
= 675 cm² .
This implies that the area of each tile is 675 cm² .
Since there are 300 tiles of such area :
Total area of the building = 300 × 675 cm²
= 202500 cm² .
Cost per square metre is Rs 4.
Evidently , we have to convert this first into metre square from centimetre square .
1 cm² = 1 cm × 1 cm
1 cm = 1/100 m .
So 1 cm² = ( 1/100 ) m × ( 1/100 ) m
= > 1/10000 m²
This means that 202500 cm² will be :
202500 / 10,000 m²
= > 2025 / 100
= > 20.25 m²
So cost will be 20.25 m² × 4
= > Rs 81 .
The cost for polishing will be Rs 81.