The floor of a building is made up of 2550 tiles which are in the zhape of a rhombus. If the dials of each tile are of length 20cm and 28cm find the cost of polishing the floor at the rate of rupees 25 m per square
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area of 1 tile= L×b
= 20×28
= 560/10000 m^2
area of 2550 tiles = (560/10000)×2550
= (56/100)×255
= (1428/10)m^2
cost of 1m^2 = 25rs
cost of (1428/10)m^2= [(1428/10)×25] rs
= 3570rs
= 20×28
= 560/10000 m^2
area of 2550 tiles = (560/10000)×2550
= (56/100)×255
= (1428/10)m^2
cost of 1m^2 = 25rs
cost of (1428/10)m^2= [(1428/10)×25] rs
= 3570rs
sonukumar985:
area of rhombus = 1/2×b×h
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