Question

The floor of a building of around 3000tiles which are rombhus shaped and each of its diagonal are 45cm and 30cm in length find the total cost of flooring if each tile cost rupees 20per m square

Answer 1

Answer:

Rs.4050

Given:

Floor of building=3000 tiles

d1=45 cm and d2=30 cm

Cost of flooring if each tile cost=Rs. 20m^2

To find:

Total cost of flooring the building

Solution:-

We know that

Area of rhombus

$= \frac{1}{2} \times d1 \times d2$

$= \frac{1}{2} \times 45 \times 30$

=$675 \: {cm}^{2}$

Area of one tile=675 cm^2

Floor of building=3000

Total area of floor=675 × 3000

=2025000 cm^2

Now 2025000 cm^2 in m^2

202.5 m

Cost of flooring=202.5 × 20

=4050

______________________

The cost of flooring the building is Rs.4050

Answer 2

Answer:

area of diagonal =1/2×45×30

=45×15

=675cm

area of total tilles= 675×3000

=2025000cm

convert into meter =202.5m

now total cost

=202.5×20

=4050rupee