Question

The floor of a drawing room consists of 2000 tiles. Each of the tiles is rectangular in
shape, of length 30 cm and width 20 cm. Find the total area of the floor.
Pls tell fast

Answer 1

Given :

• The floor of a drawing room consist of 2000 tiles .Each tiles is rectangular in shape , of dimensions ,30 cm × 20 cm.

$\rule{200pt}{3pt}$

To Find :

• Area of the room.

$\rule{200pt}{3pt}$

Solution :

~ Formula Used :

$\large{\blue{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}} \: \: {\blue{\bigstar}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Calculating the Area of Tiles :

${➙ \: {\sf{ Area = Length \times Breadth}}} \\ \\ \ {➙ \: {\sf{ Area = 30 \times 20 }}} \\ \\ \ {\qquad{\textsf{ Area of 1 Tiles = {\purple{\bf{ 600 \: cm² }}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Calculating Area of the Drawing Room :

${➙ \: {\sf{ Area \: of \: Room \: = No. \: of \: Tiles \times Area \: of \: 1 \: Tile }}} \\ \\ \ {➙ \: {\sf{ Area \: of \: Room \: = 2000 \times 600 }}} \\ \\ \ {\qquad{\sf{ Area \: of \: Room \: = {\color{darkblue}{\bf{ 1200000 \: cm² }}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Therefore :

❝ Area of the Drawing room is 1200000 cm² or 12000 m² . ❞

$\\ {\blue{\underline{\red{\rule{300pt}{9pt}}}}}$

Answer 2

✰ Given :

• The floor of a drawing room consists of 2000 tiles. Each of the tiles is rectangular in
• shape, of length 30 cm and width 20 cm.

✰ To Find :

• The total area of the floor.

✰ Solution :

• Before finding the total area of the floor, we need to find the area of each tiles .

We know that, Length × Width/Breadth = Area of the rectangle.

So,

$\\ \textsf{Length of the rectangular tiles} = \tt{30 \: cm} \\ \\ \\ \textsf{Width of the rectangular tiles = } \tt{20 \: cm} \\ \\ \\ \therefore \: {\sf{ \pmb{Area \: of \: the \: 1 \: rectangular \: tile \: = Length × Breadth}}} \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \tt{30 \: cm \times 20 \: cm} \\ \\ \\ \tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 600 \: {cm}^{2}$

Now, Finding the area of the floor of the Drawing room :

$\textsf{Area \: of \: the \: floor \: = \: No. \: of \: Tiles \: × \: Area \: of \: 1 \: Tile }\\ \\ \\ : \implies\sf{Area \: of \: the \: floor}=2000×600 \: {cm}^{2} \\ \\ \\ : \implies \sf{ Area \: of \: the \: floor \:} = {\mathfrak{\pmb{ 1200000 \: {cm}^{2} }} }$

Hence, Area of the floor of the Drawing room is 1200000 cm²