Math, asked by sujitpawsale2000, 5 hours ago

the floor of a hall has an area of 48 dm the floor is to be tiled by triangular tiles having sides 20 cm ,30cm, and 40 cm .find thre totsl cost of tiles if cost of eachg tiles is 200

Answers

Answered by raniyaunnikrishnan
0

Answer:

4900

Step-by-step explanation:

480 dm + 20cm

500 + 1000 - 100

Answered by BrainlyGovind
17

Area of floor = 36×24=864 sq. m

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required =

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36864

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36864

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36864 =24 tiles

the cost will be

200×24=4800

hope it helps you

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