the floor of a hall has an area of 48 dm the floor is to be tiled by triangular tiles having sides 20 cm ,30cm, and 40 cm .find thre totsl cost of tiles if cost of eachg tiles is 200
Answers
Answer:
4900
Step-by-step explanation:
480 dm + 20cm
500 + 1000 - 100
Area of floor = 36×24=864 sq. m
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required =
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36864
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36864
Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 36864 =24 tiles
the cost will be
200×24=4800
hope it helps you