the floor of a rectangle hall has a perimeter 150m if the cost of painting the four wall at the rate of rupees 10 per metre square is rupees 9000 find the height of the wall
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Answer:
The height of the hall is 6m.
Step-by-step explanation:
It is given that perimeter of floor = 150 m
2 ( l + b ) = 150 m
l + b = 150 / 2 m
l + b = 75 m
l = ‘75 - b’ m. => 1
Cost of painting the four walls = ₹9000
Cost of printing per sq.m = ₹ 10
Area of four walls (CSA of the hall) = 9000 / 10
= 900 m^2
=> consider the height as ‘h’.
2h (l+b) = 900 sq.m
2h ( 75-b+b) = 900 sq.m. ( from 1 )
2h (75) = 900
2h = 900/75
2h = 12
h = 12 / 2
h = 6 m
Hence, the height of the hall is 6 m .
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