the floor of a rectangle hall has a perimeter 226m. it's height is 4.5m. Find the cost of painting it's four walls at the rate of Rs. 8.40 per square metre
Answers
Answered by
1
Perimeter of the rectangular floor = 2(l+b)
= 226 m
Area of 4 walls = 2(l+b)h
= 226 × 4.5
=1017 m²
Cost of painting the 4 walls = 1017 × 8.40
= Rs. 8542.8
= 226 m
Area of 4 walls = 2(l+b)h
= 226 × 4.5
=1017 m²
Cost of painting the 4 walls = 1017 × 8.40
= Rs. 8542.8
Anonymous:
may be it will help you!!!
Answered by
1
Total cost=rate * Lateral surface area
lateral surface area = 2(l+b)*h
since 2(l+b)=perimeter = 226m,and height =h=4.5m
lateral surface area= 226*4.5
=1017sq.m
cost=rate * area
=8.4*1017
=Rs.8542.8
Ans therefore it costs Rs.8542.8
lateral surface area = 2(l+b)*h
since 2(l+b)=perimeter = 226m,and height =h=4.5m
lateral surface area= 226*4.5
=1017sq.m
cost=rate * area
=8.4*1017
=Rs.8542.8
Ans therefore it costs Rs.8542.8
Similar questions
Math,
8 months ago
Physics,
1 year ago
History,
1 year ago
Social Sciences,
1 year ago
History,
1 year ago