The floor of a rectangular hall has a perimeter 236 m.Its height is 4.5 m.Find the cost of painting its four walls (doors and windows to be ignored) at tge rate of ₹8.40 per square metre.
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2
Perimeter of floor=236m = 2(l+b)
Height of hall=4.5m
C.S.A of hall = 2(l+b)h
=236*4.5
=1062
Cost of painting 1m^2 = RS 8.4
Cost of painting 1062m^2 = 8.4*1062
=8920. 8
Height of hall=4.5m
C.S.A of hall = 2(l+b)h
=236*4.5
=1062
Cost of painting 1m^2 = RS 8.4
Cost of painting 1062m^2 = 8.4*1062
=8920. 8
Answered by
1
Perimeter of rectangle =2(l+b)
2(l+b) =236
(l+b) =236/2
(l+b) =118
height(h)=4.5
now,Area of four wall = 2h(l+b)
2×4.5×118
1062m^2
now rate of painting = $8.4/m.^2
cost of painting =1062×8.4
=$8920.8
2(l+b) =236
(l+b) =236/2
(l+b) =118
height(h)=4.5
now,Area of four wall = 2h(l+b)
2×4.5×118
1062m^2
now rate of painting = $8.4/m.^2
cost of painting =1062×8.4
=$8920.8
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