the floor of a rectangular hall has a perimeter 250 if the cost of painting the four
walls @ 10% metre square is Rupees 15000 find the hieght of the hall
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Given:-
- The floor of a rectangular hall has a perimeter 250 if the cost of painting
- The four walls 10% metre square is Rupees 15000
To find:-
- find the hieght of the hall
Solutions:-
- Let length, breadth and height of the rectangular hall l m, b m and h m.
Area of the four walls = 2lh + 2bh
= 2(l + b)h
perimeter of the floor of hall = 2(l + b)
= 250m
Area of four walls = 2(l + b)h
= 250h m²
Cost of painting per m² area = Rs 10
Cost of painting 250h m² area = Rs(250h × 10)
= Rs 2500h
The cost of painting the walls is Rs 15000.
15000 = 2500h
h = 15000/2500
h = 6
Hence, the height of the hall is 6m.
Some Important:-
- Total surface area = 2(lb + bh + hl)
- Lateral surface area = 2h(l + b)
- Volume = l × b × h
Where,
- L = Length
- B = Breadth
- H = Height
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