The floor of a rectangular hall has a perimeter 250 m and its length and breadth are in the ratio 13:12.If the cost of painting the four walls and ceiling at the rate of 5rs. per square metre is rs.27,000.Find the height of the hall.
Answers
Answered by
34
WE KNOW PERIMETER IS 250M
AREA TO BE PAINTED = P*H
=250*H
Since the total cost=27000rs at the rate of 5rs /sqm
so total area to be painted = 27000/5
=5400sqm
=250*h=5400
=5400/250=h
=21.6=h
hence height = 21.6
AREA TO BE PAINTED = P*H
=250*H
Since the total cost=27000rs at the rate of 5rs /sqm
so total area to be painted = 27000/5
=5400sqm
=250*h=5400
=5400/250=h
=21.6=h
hence height = 21.6
Answered by
15
krishnaudhai11584
Answer:21.6
Step-by-step explanation:
Perimeter=250
LSA of a cuboid = 27000
=27000/5
=5400sqm
=250*h=5400
=5400/250=h
=21.6=h
Answer:height = 21.6
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