Math, asked by agebelargandu, 1 year ago

The floor of a rectangular hall has a perimeter 250 m and its length and breadth are in the ratio 13:12.If the cost of painting the four walls and ceiling at the rate of 5rs. per square metre is rs.27,000.Find the height of the hall.

Answers

Answered by hrushikesh2002
34
WE KNOW PERIMETER IS 250M
AREA TO BE PAINTED = P*H
=250*H
Since the total cost=27000rs at the rate of 5rs /sqm
so total area to be painted = 27000/5
=5400sqm
=250*h=5400
=5400/250=h
=21.6=h
hence height = 21.6


Answered by krishnaudhai11581
15

krishnaudhai11584

Answer:21.6



Step-by-step explanation:

Perimeter=250

LSA of a cuboid = 27000

=27000/5

=5400sqm

=250*h=5400

=5400/250=h

=21.6=h

Answer:height = 21.6


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