Question

The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of rs 10 per m2 is 15000, find the height of the hall.

Answer 1

Answer:

60

2(lh+bh) area of four walls

so 2h(l+b) by taking h common 2(l+b) is perimeter so h*25 is area of four walls

so area is 15000/10=1500

so 1500 /25 is 60

Answer 2

Height of the wall is 6 m.  

Step-by-step explanation:

Given :

Perimeter of a rectangular hall = 250 m

∴ 2(i+b) = 250

$\text{l}+\text{b} = \frac{250}{2} = 125$

Area of four walls = Area of cuboid - Area of the ceiling - Area of floor

                              = 2(lb+bh+lh) - lb - lb

                               = 2 lb + 2 bh + 2 lh - 2 lb

                               = 2 bh + 2 lh

                                = 2h (b+l)

                                =2h(125) = 250h m²

Cost of painting four walls at Rs.10 per m² is Rs. 15000

Cost of painting = 250h x 10

15000 = 250h x 10

$\text{h} = \frac{15000}{2500} = 6$

∴ height of the wall is 6 m          

To Learn More....

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