Question

The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs 10 meter per square is Rs 15000, find the height of the hall. Please answer this question

Answer 1

Answer:

6m

Step-by-step explanation:

Given perimeter of the rectangular floor = 250 m

Hence 2(l + b) = 250

Therefore, (l + b) = 125 --- (1)

Area of four walls, A = 15000/10 = 1500 sq m

That is 2h(l + b) = 1500

2h x 125 = 1500

h = 1500/250 = 6

Thus, the height of the hall is 6 m.

Answer 2

Answer:

Height of the hall is 6m.

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Step-by-step explanation:

Let length,breadth and height of the rectangular hall be l,b and h respectively.

Perimeter of the hall=2(l+b)

250m=2(l+b)

125m=l+b. ......(i)

Area of 4 walls=Area of cuboid-Area of floor-Area of top

=2(lb+bh+hl)-l×b-l×b

=2(lb+bh+hl)-lb-lb

=2(lb)+2(bh)+2(hl)-2(lb)

=2lh+2bh

=2h(l+b)

=2h×125. {from(i)}

=250 h m²

Area of four walls=250 h m²

Cost of painting per 1m²=Rs.10

Cost ot painting 250hm²=Rs.10×250h

15000=2500h

15000/2500=h

6=h

Therefore,the height of the wall is 6m.