The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of ₹10 per m2 is ₹15000, find the height of the hall.
Answers
Step-by-step explanation:
lateral surface area = 2 x height (length + wide)
perimeter = 2( length + width)
length + wide = 125
area costing of
lateral surface are painting = 15000/10=1500
m^2
height =1500/250=6 m
✦ Question :-
The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of ₹10 per m2 is ₹15000, find the height of the hall.
Height of Hall [H]
Given:
⠀⠀⠀⠀⠀⠀⠀⠀
Perimeter of the hall = 250 m
Cost of painting the four walls at the rate of ₹10 per m² is ₹15000
⠀⠀⠀⠀⠀⠀⠀⠀
To find:
⠀⠀⠀⠀⠀⠀⠀⠀
What is the Height of the hall ?
Solution:
⠀⠀⠀⠀⠀⠀⠀⠀
Consider the height of the hall be h metres.
So , ⠀⠀⠀⠀⠀⠀⠀⠀
Area of the four walls = Perimeter of the floor × Height
⠀⠀⠀⠀⠀⠀⠀⠀
= 250 × h
⠀⠀⠀⠀⠀⠀⠀⠀
= 250 h m²
⠀⠀⠀⠀⠀⠀⠀⠀
From the given cost of painting of 1 square metre was ₹10 then cost of painting of the four walls is
= 250 h × 10
⠀⠀⠀⠀⠀⠀⠀⠀
= ₹ 2500 h
⠀⠀⠀⠀⠀⠀⠀⠀
As per the Question the cost of painting of the four walls is ₹ 15000.
⠀Then , 2500 h = 15000
⠀⠀⠀⠀⠀⠀⠀⠀
h = 15000/2500
H = 6
⠀⠀⠀⠀⠀⠀⠀⠀