The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four
walls at the rate of Rs 10 per m’ is Rs 15000, find the height of the hall.
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Answered by
6
Answer:
Given:
Perimeter=250m
⇒Area of 4 walls =2lh+2bh
=2(b+l)h
⇒Perimeter of floor of wall =2l+2b
⇒2(l+b)=250 m
∴ Area of 4 walls =2(l+b)h
=250h m
2
⇒Cost of painting per m
2
area = Rs. 10
⇒Cost of painting 250h m
2
area = Rs(250h×10)
= Rs.2500h
⇒Painting cost of walls = Rs. 15000
⇒2500h=15000
⇒h=
2500
15000
⇒h=6m
Answered by
3
Answer:
- Perimeter of Floor = 250 m
- Cost of painting four walls = Rs. 15000
- Rate of painting = Rs. 10 per m²
- Height of wall = ?
• According to the Question :
⇢ Cost of painting four walls = Rs. 15000
⇢ CSA × Rate = Rs. 15000
⇢ 2(L + B) × h × 10 = 15000
- Perimeter is given : 2(L + B) = 250 m
⇢ 250 × h × 10 = 15000
⇢ h × 2500 = 15000
⇢ h = 15000 / 2500
⇢ h = 6 m
∴ Hence, height of the hall is 6 meter.
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