Math, asked by simranjeet49, 9 months ago

the floor of a rectangular hall has a perimeter 250 metre if the cost of painting the floor walls @ rupees 10 per metre square is rupees 15000
find the height of the hall

Answers

Answered by veydaantgarg
1
250 X __X10=15000
2500X_=15000
_=15000/2500
Answered by skyfall63
2

The height of the rectangular hall is 6 m.

Explanation:

Given: Perimeter of the hall = 250 m

Cost = 10/m² = Rs. 15000

Height of the hall = ?

Perimeter of the rectangular hall = 2(l + b) [l = length, b = breadth]

250 = 2(1 + b)

l + b = 125 m ---- (1)

Area of four walls = Area of cuboid - Area of floor - Area of top

Area of cuboid = 2(lb + bh + lh); Area of floor = l x b; Area of top = l x b

= 2(lb + bh + lh) - (l x b) - (l x b)

= 2lb + 2bh + 2lh - 2lb

= 2hb + 2lh

= 2h(1+ b)

= 2h(125)

Area of four walls = 250 h m²

Cost of painting the floor walls 250h m² area = Rs. 10 x 250h

15000 = 2500h

h = \frac{15000}{2500}

h = 6 m.

The height of the wall = 6 m.

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