the floor of a rectangular hall has a perimeter 250m . if the cost of painting the four walls at the rate of rs 10 per m sq is Rs 15000 , find the height of the hall
Answers
Answered by
6
I hope this will help you.
Area of four walls =15000/10=1500m²
2(l+b) *h=1500. (Perimeter=2(l+b) =250)
250*h=1500
H=1500/250
6m=height
Area of four walls =15000/10=1500m²
2(l+b) *h=1500. (Perimeter=2(l+b) =250)
250*h=1500
H=1500/250
6m=height
Answered by
10
Perimeter = 2(l+b)
250 = 2(l+b)
125 = l +b -------(1)
lateral surface area of cubiod or are of 4 Walls = Rs.15000/ Rs.10 per m
= 1500 m^2
formula of lateral surface area of cuboid = 2h(l+b)
so , 2h(l+b) = 1500 (l+b= 125)----(1)
2 × h × 125 = 1500
h = 1500/ 2× 125
= 1500/ 250
= 6 m
250 = 2(l+b)
125 = l +b -------(1)
lateral surface area of cubiod or are of 4 Walls = Rs.15000/ Rs.10 per m
= 1500 m^2
formula of lateral surface area of cuboid = 2h(l+b)
so , 2h(l+b) = 1500 (l+b= 125)----(1)
2 × h × 125 = 1500
h = 1500/ 2× 125
= 1500/ 250
= 6 m
Sonalika17:
Thank you
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