the floor of a rectangular hall has a perimeter 250m.if the cost of painting the four walls at the rate of 10 per m* is 15000,find the height of the hall.
(Hint:area of the four walls=lateral surface area
Answers
Given :-
Perimeter of the floor with a rectangular hall = 250 m
Cost of painting the four walls at the rate of 10 per m² = Rs. 15000
To Find :-
The height of the hall.
Solution :-
We know that,
- l = Length
- b = Breadth
- h = Height
- a = Area
According to the question,
Area of four walls = 2lh + 2bh
= 2 (l + b) h
Given that,
Perimeter of the floor of hall = 2 (l + b) = 250 m
Area of four walls = 2 (l + b) h = 250h m²
Cost of painting per square meter = Rs. 10
Then,
Cost of painting 250h square meter area = Area of four walls × Cost of painting per square meter
Substituting their values,
Cost of painting 250h square meter = 250h × 10
Cost of painting = Rs.2500h
In the question,
Given that, the cost of paining the walls is Rs. 15000
15000 = 2500h
h = 6
Therefore, the height of the hall is 6 m
Step-by-step explanation:
Given:
Perimeter=250m
⇒Area of 4 walls =2lh+2bh
=2(b+l)h
⇒Perimeter of floor of wall =2l+2b
⇒2(l+b)=250 m
∴ Area of 4 walls =2(l+b)h
=250h m
2
⇒Cost of painting per m
2
area = Rs. 10
⇒Cost of painting 250h m
2
area = Rs(250h×10)
= Rs.2500h
⇒Painting cost of walls = Rs. 15000
⇒2500h=15000
⇒h=
2500
15000
⇒h=6m