The floor of a rectangular hall has a perimeter 250m.If the cost of painting of the four wall at the rate of rupees 10 per m square is rupees 15000, find the height of the wall
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2 x (l+b) = 250
( l + b ) = 250/2
l + b = 125
rate - 10/sq.m
cost - 15000
area = cost/rate
area = 15000/10
= 1500 sq.m
2 x h x ( l + b ) = 1500
but ( l + b ) = 125
So, 2 x 125 x h = 1500
250 x h = 1500
h = 1500/250
h = 6m
Hence Proved.
( l + b ) = 250/2
l + b = 125
rate - 10/sq.m
cost - 15000
area = cost/rate
area = 15000/10
= 1500 sq.m
2 x h x ( l + b ) = 1500
but ( l + b ) = 125
So, 2 x 125 x h = 1500
250 x h = 1500
h = 1500/250
h = 6m
Hence Proved.
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2
Step-by-step explanation:
Let length, breadth, and height of the rectangular hall be l, b, and h respectively.
Area of four walls = 2lh+2bh
= 2(l+b)h
Perimeter of the floor of hall = 2(l+b)
= 250 m
Area of four walls = 2(l+b) h = 250h m2
Cost of painting per square meter area = Rs.10
Cost of painting 250h square meter area = Rs (250h×10) = Rs.2500h
However, it is given that the cost of paining the walls is Rs. 15000.
15000 = 2500h
Or h = 6
Therefore, the height of the hall is 6 m.
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