The floor of a rectangular hall has a perimeter 250m its height is 6m find cost of painting of four walls( ( including doors) at the rate of rupees 6 per square metre
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Answered by
34
Given perimeter of floor = 250m
We know that, perimeter = 2(l + b)
=> 2(l + b) = 250 m
Now given that height = 6m
Here, we have to find lateral surface area as the walls are to be painted.
Lateral surface area = 2(l + b) × h
=> 250 × 6
= 1500 m²
Since doors are also be painted, no area is excluded. Hence cost of painting = 6 × 1500 = ₹9,000
Hope it helps
We know that, perimeter = 2(l + b)
=> 2(l + b) = 250 m
Now given that height = 6m
Here, we have to find lateral surface area as the walls are to be painted.
Lateral surface area = 2(l + b) × h
=> 250 × 6
= 1500 m²
Since doors are also be painted, no area is excluded. Hence cost of painting = 6 × 1500 = ₹9,000
Hope it helps
Mankuthemonkey01:
Thank you both ❤️
Answered by
24
Perimeter of floor = 250m
Perimeter = 2(l + b)
=> 2(l + b) = 250 m
Height = 6m
Lateral surface area as the walls are to be painted.
Lateral surface area = 2(l + b) × h
=> 250 × 6
= 1500 m²
:- Doors are also be painted :-
:- Area is not excluded :-
:- Hence cost of painting :-
= 6 × 1500
= ₹9,000
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