Question

the floor of a rectangular hall has a perimeter 250m lf the cost of painting the four wall at the rate of ₹10per m is ₹15000fond the height of the hall
​

Answer 1

Solution :-

Let ,

• length of rectangular hall = l
• Breadth of rectangular hall = b
• Height of rectangular hall = h

→Area of four walls = 2lh + 2bh

→ 2(l + b)h

______________

Perimeter of the floor of hall :-

⠀= 2(l+b)⠀⠀

⠀= 250m

Area of four walls :-

⠀= 2(l+b)h

⠀= 250h${m}^{2}$

___________

⟹Cost of painting per ${m}^{2}$= Rs 10

however it is given that :-

⟹ cost of painting the wall is = Rs 15000

⠀⟹ 15000 = 2500h

⠀⟹ h = 6

⠀∴ height of the hall is 6m

Answer 2

Answer:

Height = 6m

-----------------------------------------------------------------------------------

Explanation:

----------------------------------------------------------------------------------

Given:

Perimeter = 250m

Cost of painting the four walls at the rate of ₹10 m² = ₹15000

----------------------------------------------------------------------------------

To Find: The required height

Lateral Surface Area of a Cuboid = Perimeter x Height

                                                                      OR

                                                 2 x ( length + breadth) x height

We know that the perimeter is 250m. so,

250 x height (h) x 10 = 15000

[ here 250 is the perimeter, 10 is the cost of painting the walls per m² and 15000 is the rate of painting all four walls.]

Cost of painting the four walls = 10 x 250h

                                                  = 2500h

2500h = 15000

         h = $\frac{15000}{2500}$

            = 6

-------------------------------------------------------------------------------

SOLUTION:

∴ The required height = 6m

--------------------------------------------------------------------------------

Please mark as brainliest and thank this answer pls

                                   \

                            (*^▽^*)