The floor of a rectangular hall has a perimeter 260 m. The cost of painting the four walls at the rate of 10 per m² is 13,000. Find the height of the hall
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Let the length, breadth and height of the rectangular Hall be l m, b m and h m respectively
Perimeter = 260 m
= 2(l+b) = 260
= l+b= 130 --(1)
Area of the four walls
= 13000/10 = 1300 m^2
= 2(l+b)h = 1300
= (l+b)h = 650
= 130h = 650 [ using (1) ]
= h = 650/130
= h = 5m
Hence, the height of the Hall is 6m.
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