Question

The floor of a rectangular hall has a perimeter of 250m. Its height is 6m . Find the cost of painting its four walls at the rate of Rs 6 per square meter

Answer 1

$\bf\large{\underline{Question:-}}$

the floor of a rectangular hall has a perimeter of cost 250m. its height is 6cm find the cost of painting its 4 wall at the rate of 6₹ sq.m

$\bf\large{\underline{Given :-}}$

perimeter = 250 sq.m

height=6cmm

cost of painting of 4 wall at the rate of 6₹

$\bf\large{\underline{To\:find:-}}$

cost of painting = ?

$\bf\large{\underline{Solution:-}}$

$\tt→ Perimeter\:of\:floor = 250m\\\tt→ 2(l+b)=250\\\tt→ height = 6cm$

Lateral surface area = 2(l+b)×h

→ 250×6

→ 1500$\bf m^2$

$\tt→ 1m^2\:rate\:of\: painting=6 Rs.\\\tt→ 1500×6 = 9000 Rs.$

Hence,

the cost of painting of its 4 wall is= 9000 .Rs

Answer 2

Given :

• The floor of a rectangular hall has a perimeter of 250m.

• Height of the rectangular hall = 6 cm.

To find :

• The cost of painting its four walls at the rate of Rs 6 per square meter =?

Step-by-step explanation :

It is Given that,

Perimeter of the rectangular hall = Perimeter of the rectangle = 2 ( length + breadth)

Substituting the values in the above formula, we get,

2(length +breadth) = 250

Now,

As We know that,

Curved Surface Area of cuboid = 2(l+b) × h

Substituting the values in the above formula, we get,

= 250 × 6

= 1500.

Therefore, Curved Surface Area of cuboid = 1500 m².

Now,

The cost of painting its four walls at the rate of Rs 6 per square meter = Curved Surface Area of cuboid × 6

Substituting the values, we get,

= 1500 × 6

= 9000.

Therefore, the cost of painting its four walls at the rate of Rs 6 per square meter = Rs. 9000.