the floor of a rectangular has perimeter 300 cm. Let the cost of painting of four walls of rupees 12 per cm is Rs 24000 then find the height of hall
Answers
Answered by
37
we have perimeter = 2(l+b) = 300cm
CSA of rectagular hall = cost / Cost of painting per cm²
= 24000/12 = 2000cm²
CSA of rectagular hall = 2(l+b)h = 2000cm²
= 300h = 2000
= h = 2000/300 = 6.66cm
Mark it as brainliest answer PLZ.............
CSA of rectagular hall = cost / Cost of painting per cm²
= 24000/12 = 2000cm²
CSA of rectagular hall = 2(l+b)h = 2000cm²
= 300h = 2000
= h = 2000/300 = 6.66cm
Mark it as brainliest answer PLZ.............
luckybadgujar9ovpgsr:
plz.......mark it as brainliest answer.... Prashant
Answered by
5
Answer:Perimeter of a rectangular hall=300cm
2(l+b) =300
(l+b) =300/2
(l+b) =150cm
Rate=24000/12
=2000
Now, 2h(l+b) =2000
2×h×150=2000
=h =2000/300
Ans =20/3.
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