Math, asked by naitri586, 6 months ago

The floor of a room consists of 1500 tiles which are rhombus shaped and each of its diagonals are 40cm and 25cm in length. Find the total cost of polishing the floor, if the cost per m² is ₹4 .​

Answers

Answered by diva4769
41

Answer:

Cost = Area × Rate

And Area of Rhombus = 1/2 d1× d2

1/2×40×25 =500

tiles = 500 × 1500 = 750,000 ( ar. of flore )

price = rate × ar. of flore

750000 ÷ (100)( 100) --- changing cm to m

= 75

= 75 × 4 = 300

cost of polishing is 300Rs.

Answered by yanathakarias
1

Answer:

₹300

Step-by-step explanation:

let, cost= area×rate

and area of rhombus =1/2d1×d 2

1/2×40×25=50

tiles=500×1500=750,000

car. of Flore

price=rate×ar.of Flore

750000÷(100)(100)----

changing custom

=75

=75×4=300

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