the floor of a room in rectangular in shape its length is 6 cm and breadth is 5 metre height of the room is 4 metre find the area of the four walls of the room
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Dimensions of the rectangular room=6m×5m×4m
where l=6m, b=5m and h=4m
Total Surface area of the four walls=Lateral surface area of the cuboid
⇒Total Surface area of the four walls=2(bh+lh)
=2h(b+l)
=2×4(5+6)
=88sq.m
∴Total Surface area of the four walls=88sq.m
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Answer:
Sorry I think you have got the question wrong
I'm answering the question for 6m instead of 6cm
I hope that is what you wanted.
Step-by-step explanation:
The answer will be 2(24+20)
i.e.88
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