Question

the floor of a room is 12m long and 6m wide. The floor of this is to be fitted with tiles of dimension 10cm * 2cm . What will be the total expence in rupees if the cost of tiling is ₹5 a tile​

Answer 1

Answer:

Rs. 180000

Step-by-step explanation:

area of the rectangular floor: 1200 cm *600 cm

area of the tile: 10 cm*2 cm

no. of tiles : 1200 cm* 600 cm/10 cm*2 cm

=36000 tiles

cost of tilling 1 tile = Rs.5

Cost of tiling 36000 tiles = 5*36000 = rs. 180000

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Answer 2

Given: dimensions of the floor of the room is 12m long and 6m wide.

Dimensions of the tile is $\[10cm \times 2cm\]$

To find: the total expense of tiling the floor if the cost of tiling is Rs. 5 a tile.

Solution:

Find the area of the rectangular floor.

area of the rectangular floor$\[ = 1200{\rm{ }}cm \times 600{\rm{ }}cm\]$

Find the area of a tile.

area of the tile$\[ = 10{\rm{ }}cm \times 2{\rm{ }}cm\]$

Find the number of tiles required.  

no. of tiles$\[ = \frac{{1200{\rm{ }}cm \times 600{\rm{ }}cm}}{{10{\rm{ }}cm \times 2{\rm{ }}cm}}\]$

                $\[\begin{array}{l} = 60 \times 600\\ = 36000\,tiles\end{array}\]$

Know that from the question, the cost of tilling 1 tile $= Rs.5$

Find the cost of tiling the whole floor with 36000 tiles.

Cost of tiling 36000 tiles $\[ = 5 \times 36000\]$

                                         $\[ = Rs.{\rm{ }}180000\]$

Hence, the  total expense of tiling the floor if the cost of tiling is Rs. 5 a tile is Rs. 180000.