the floor of a room is 3 M wide and 4 long how many square tile of side 50 cm are required to cover the floor of the room
Answers
Answer:
48 tiles
Step-by-step explanation:
Area of rectangle = length×breadth
Area of the floor of room = 3×4 = 12m² = 1,20, 000 cm²
1m² = 10,000 cm²
Area of square = side×side
Area of 50 cm square tile = 50× 50 = 2500 cm²
No of tiles = area of floor / area of one square tile
No of tiles = 120000/2500
= 1200/25 = 48
48 tiles
So there are 48 square tiles in the room
Answer:-
According to the Question
It is given that,
- Length of room ,L = 3m = 300cm
- Breadth of room ,B = 4m = 400cm
- Side of square tiles ,S = 50cm
We have to calculate the no. tiles required to cover the floor of the room.
Firstly we calculate the area of room .
- Area of Room = Length × Breadth
Substitute the value we get
→ Area of Room = 300 × 400
→ Area of Room = 120000 cm²
Now, Calculating the area occupied by one titles .
- Area of Square tiles = side × side
substitute the value we get
→ Area of Square tiles = 50×50
→ Area of Square tiles = 2500cm²
So, the no. of titles = Area of Room/Area of Square tiles
→ No. of tiles = 120000/2500
→ No. of tiles = 1200/25
→ No. of tiles = 48
- Hence, the number of tiles required to cover the floor of the room is 48 .
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