Question

The floor of a room is 4.84 m long and 3.1 m broad. It is to be covered with rectangular tiles of size 22 cm by 10 cm. Find the cost of the tiles at the rate of 6.50 per tile.​

Answer 1

♣GIVEN :

• Length of the floor of the room (l) = 4.84 m = 484 cm

• Breadth of the floor of the room (b) = 3.1 m = 310 cm

• Length of each tile (l) = 22 cm

• Breadth of each tile (b) = 10 cm

• Rate of paving (r) = ₹ 6.50/tile

♣TO FIND :

• Cost of the tiles (c)

♣SOLUTION :

❶ First we need to find the area of the floor:-

❐ USING FORMULAE :

$\huge \boxed{ \sf{A = \bigg(l \: \times b \bigg) unit}}$

✯ WHERE :-

• A = Area

• l = length

• b = breadth

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➲ Putting all values :-

$➨ \:\bf{A = \bigg( 484 \times 310 \bigg)} \: cm^{2}$

$➠ \: \underline{\boxed{\bf{A = 150040} \: {cm}^{2} }}$

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❷ Now we have to find the area of each tile:-

❐ USING FORMULAE :

$\huge \boxed{ \sf{A = \bigg(l \: \times b \bigg) unit}}$

✯ WHERE :-

• A = Area

• l = length

• b = breadth

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➲ Putting all values :-

$➨ \:\bf{A = \bigg( 22\times 10 \bigg)} \: cm^{2}$

$➠ \: \underline{\boxed{\bf{A = 220} \: {cm}^{2} }}$

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❸ Now let us find the number of tiles required for paving the floor:-

❐ USING FORMULAE :

$\huge \boxed{ \sf{ Tiles \: Required = \bigg( \dfrac{ Area \: of \: the \: floor }{Area \: of \: each \: tile} \bigg)}}$

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➲ Putting all values :-

$➨ \:\bf{Tiles \: required= \dfrac{15004 \cancel0}{22 \cancel0} }$

$➨ \:\bf{Tiles \: required= \dfrac{ \cancel{15004} ^{682}}{ \cancel{22}_{1} }}$

$➠ \: \underline{\boxed{\bf{Tiles \: required= 682} }}$

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❹ Finally we find the cost of the tiles:-

We have :-

❍ Rate per tile = ₹ 6.50

❐ USING FORMULAE :

$\huge \boxed{ \sf{ Cost \: of \: tiles= ₹\bigg( Rate × \: tiles \: required \bigg)} }$

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➲ Putting all values :-

$➨ \:\bf{ Cost \: of \: tiles \: = ₹\bigg(6.50 \times 682 \bigg) }$

$➠ \: \underline{ \boxed{\bf{ Cost \: of \: tiles \: = ₹4433 }}}$

♣ANSWER :

• Our required answer is ₹4433

Answer 2

GiveN:

• Dimension of the floor = 4.84 m × 3.1 m
• Dimension of each tile = 22 cm × 10 cm
• Cost of each tile = Rs. 6.5

To FinD:

• Total cost of tiling the floor?

Step-wise-Step Explanation:

The total number of tiles with the given dimension will cover the entire area of the floor. Hence,

$\large{\cdot\:{ \sf{No. \: of \: tiles = \dfrac{Area \: of \: the \: floor}{Area \: of \: each \: tile} }}}$

Finding the area of floor:

➛ L × B

➛ 4.84 m × 3.1 m

➛ 484 cm × 310 cm

Finding the area of each tile:

➛ l × b

➛ 22 cm × 10 cm

Now finding no. of tiles:

= 484 cm × 310 cm / 22 cm × 10 cm

= 22 × 31 tiles

= 682 tiles

It is given that,

➛ Cost of 1 tile = Rs. 6.50

➛ Cost of 682 tiles = Rs. 6.5 × 682

➛ Cost of 682 tiles = Rs. 4433

Hence,

The cost of tiling the floor:

$\huge{ \boxed{ \sf{ \green{Rs.4433}}}}$